Michael Holmes
July 15th, 2012, 08:40 PM
This is a basic question, but I just want to be sure I'm not making a mistake.
I have been using a 1/3" sensor camera.
Now I will be using two FS100 cameras for two-camera shoots, and I am checking the lenses I need.
With the Super 35mm sensor size, the needed focal length seems huge.
My math is the basic math for similar triangles:
L/W = focal length/sensor width
So, if I want a close-up of say 4 ft width, and I want to shoot it from the back of a club, say 35 ft away from the musician, I would get:
focal length = 35 x 23.6mm/4 = 206mm
If I want a 3 ft. wide close-up, the focal length would need to be:
focal length = 35 x 23.6/3 = 275mm
This is low light shooting and I plan to go with a Nikon 70-200 f/2.8 lens for the close-up camera. But if my math is right, the zoom will be near max most of the time. I don't want to get real close to the musicians, so I stay out of the way of the other camera shots.
I am sure I am making a math mistake.........what is it?
I have been using a 1/3" sensor camera.
Now I will be using two FS100 cameras for two-camera shoots, and I am checking the lenses I need.
With the Super 35mm sensor size, the needed focal length seems huge.
My math is the basic math for similar triangles:
L/W = focal length/sensor width
So, if I want a close-up of say 4 ft width, and I want to shoot it from the back of a club, say 35 ft away from the musician, I would get:
focal length = 35 x 23.6mm/4 = 206mm
If I want a 3 ft. wide close-up, the focal length would need to be:
focal length = 35 x 23.6/3 = 275mm
This is low light shooting and I plan to go with a Nikon 70-200 f/2.8 lens for the close-up camera. But if my math is right, the zoom will be near max most of the time. I don't want to get real close to the musicians, so I stay out of the way of the other camera shots.
I am sure I am making a math mistake.........what is it?